Optimal. Leaf size=165 \[ \frac{d^2 \left (b^2-4 a c\right )^2 (b+2 c x) \sqrt{a+b x+c x^2}}{128 c^2}-\frac{d^2 \left (b^2-4 a c\right ) (b+2 c x)^3 \sqrt{a+b x+c x^2}}{64 c^2}+\frac{d^2 \left (b^2-4 a c\right )^3 \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{256 c^{5/2}}+\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c} \]
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Rubi [A] time = 0.0887438, antiderivative size = 165, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {685, 692, 621, 206} \[ \frac{d^2 \left (b^2-4 a c\right )^2 (b+2 c x) \sqrt{a+b x+c x^2}}{128 c^2}-\frac{d^2 \left (b^2-4 a c\right ) (b+2 c x)^3 \sqrt{a+b x+c x^2}}{64 c^2}+\frac{d^2 \left (b^2-4 a c\right )^3 \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{256 c^{5/2}}+\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c} \]
Antiderivative was successfully verified.
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Rule 685
Rule 692
Rule 621
Rule 206
Rubi steps
\begin{align*} \int (b d+2 c d x)^2 \left (a+b x+c x^2\right )^{3/2} \, dx &=\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c}-\frac{\left (b^2-4 a c\right ) \int (b d+2 c d x)^2 \sqrt{a+b x+c x^2} \, dx}{8 c}\\ &=-\frac{\left (b^2-4 a c\right ) d^2 (b+2 c x)^3 \sqrt{a+b x+c x^2}}{64 c^2}+\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c}+\frac{\left (b^2-4 a c\right )^2 \int \frac{(b d+2 c d x)^2}{\sqrt{a+b x+c x^2}} \, dx}{128 c^2}\\ &=\frac{\left (b^2-4 a c\right )^2 d^2 (b+2 c x) \sqrt{a+b x+c x^2}}{128 c^2}-\frac{\left (b^2-4 a c\right ) d^2 (b+2 c x)^3 \sqrt{a+b x+c x^2}}{64 c^2}+\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c}+\frac{\left (\left (b^2-4 a c\right )^3 d^2\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{256 c^2}\\ &=\frac{\left (b^2-4 a c\right )^2 d^2 (b+2 c x) \sqrt{a+b x+c x^2}}{128 c^2}-\frac{\left (b^2-4 a c\right ) d^2 (b+2 c x)^3 \sqrt{a+b x+c x^2}}{64 c^2}+\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c}+\frac{\left (\left (b^2-4 a c\right )^3 d^2\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{128 c^2}\\ &=\frac{\left (b^2-4 a c\right )^2 d^2 (b+2 c x) \sqrt{a+b x+c x^2}}{128 c^2}-\frac{\left (b^2-4 a c\right ) d^2 (b+2 c x)^3 \sqrt{a+b x+c x^2}}{64 c^2}+\frac{d^2 (b+2 c x)^3 \left (a+b x+c x^2\right )^{3/2}}{12 c}+\frac{\left (b^2-4 a c\right )^3 d^2 \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{256 c^{5/2}}\\ \end{align*}
Mathematica [A] time = 0.456914, size = 211, normalized size = 1.28 \[ \frac{1}{3} d^2 (b+2 c x) \sqrt{a+x (b+c x)} \left ((a+x (b+c x))^2-\frac{(a+x (b+c x)) \left (2 (b+2 c x) \sqrt{\frac{c (a+x (b+c x))}{4 a c-b^2}} \left (4 c \left (5 a+2 c x^2\right )-3 b^2+8 b c x\right )+3 \sqrt{c} \sqrt{4 a-\frac{b^2}{c}} \left (4 a c-b^2\right ) \sinh ^{-1}\left (\frac{b+2 c x}{\sqrt{c} \sqrt{4 a-\frac{b^2}{c}}}\right )\right )}{256 c (b+2 c x) \left (\frac{c (a+x (b+c x))}{4 a c-b^2}\right )^{3/2}}\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.049, size = 406, normalized size = 2.5 \begin{align*} -{\frac{{a}^{2}{d}^{2}b}{8}\sqrt{c{x}^{2}+bx+a}}+{\frac{{b}^{2}{d}^{2}x}{24} \left ( c{x}^{2}+bx+a \right ) ^{{\frac{3}{2}}}}+{\frac{{d}^{2}{b}^{3}}{48\,c} \left ( c{x}^{2}+bx+a \right ) ^{{\frac{3}{2}}}}-{\frac{{d}^{2}{b}^{5}}{128\,{c}^{2}}\sqrt{c{x}^{2}+bx+a}}-{\frac{a{d}^{2}b}{12} \left ( c{x}^{2}+bx+a \right ) ^{{\frac{3}{2}}}}+{\frac{2\,c{d}^{2}x}{3} \left ( c{x}^{2}+bx+a \right ) ^{{\frac{5}{2}}}}+{\frac{{d}^{2}b}{3} \left ( c{x}^{2}+bx+a \right ) ^{{\frac{5}{2}}}}+{\frac{3\,{b}^{2}{d}^{2}{a}^{2}}{16}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){\frac{1}{\sqrt{c}}}}-{\frac{3\,{d}^{2}{b}^{4}a}{64}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{3}{2}}}}+{\frac{{b}^{2}{d}^{2}xa}{8}\sqrt{c{x}^{2}+bx+a}}-{\frac{{d}^{2}{b}^{4}x}{64\,c}\sqrt{c{x}^{2}+bx+a}}+{\frac{{d}^{2}{b}^{3}a}{16\,c}\sqrt{c{x}^{2}+bx+a}}+{\frac{{d}^{2}{b}^{6}}{256}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{5}{2}}}}-{\frac{c{d}^{2}ax}{6} \left ( c{x}^{2}+bx+a \right ) ^{{\frac{3}{2}}}}-{\frac{{a}^{2}c{d}^{2}x}{4}\sqrt{c{x}^{2}+bx+a}}-{\frac{{a}^{3}{d}^{2}}{4}\sqrt{c}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.86534, size = 1071, normalized size = 6.49 \begin{align*} \left [-\frac{3 \,{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} \sqrt{c} d^{2} \log \left (-8 \, c^{2} x^{2} - 8 \, b c x - b^{2} + 4 \, \sqrt{c x^{2} + b x + a}{\left (2 \, c x + b\right )} \sqrt{c} - 4 \, a c\right ) - 4 \,{\left (256 \, c^{6} d^{2} x^{5} + 640 \, b c^{5} d^{2} x^{4} + 16 \,{\left (33 \, b^{2} c^{4} + 28 \, a c^{5}\right )} d^{2} x^{3} + 8 \,{\left (19 \, b^{3} c^{3} + 84 \, a b c^{4}\right )} d^{2} x^{2} + 2 \,{\left (b^{4} c^{2} + 144 \, a b^{2} c^{3} + 48 \, a^{2} c^{4}\right )} d^{2} x -{\left (3 \, b^{5} c - 32 \, a b^{3} c^{2} - 48 \, a^{2} b c^{3}\right )} d^{2}\right )} \sqrt{c x^{2} + b x + a}}{1536 \, c^{3}}, -\frac{3 \,{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} \sqrt{-c} d^{2} \arctan \left (\frac{\sqrt{c x^{2} + b x + a}{\left (2 \, c x + b\right )} \sqrt{-c}}{2 \,{\left (c^{2} x^{2} + b c x + a c\right )}}\right ) - 2 \,{\left (256 \, c^{6} d^{2} x^{5} + 640 \, b c^{5} d^{2} x^{4} + 16 \,{\left (33 \, b^{2} c^{4} + 28 \, a c^{5}\right )} d^{2} x^{3} + 8 \,{\left (19 \, b^{3} c^{3} + 84 \, a b c^{4}\right )} d^{2} x^{2} + 2 \,{\left (b^{4} c^{2} + 144 \, a b^{2} c^{3} + 48 \, a^{2} c^{4}\right )} d^{2} x -{\left (3 \, b^{5} c - 32 \, a b^{3} c^{2} - 48 \, a^{2} b c^{3}\right )} d^{2}\right )} \sqrt{c x^{2} + b x + a}}{768 \, c^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} d^{2} \left (\int a b^{2} \sqrt{a + b x + c x^{2}}\, dx + \int b^{3} x \sqrt{a + b x + c x^{2}}\, dx + \int 4 c^{3} x^{4} \sqrt{a + b x + c x^{2}}\, dx + \int 4 a c^{2} x^{2} \sqrt{a + b x + c x^{2}}\, dx + \int 8 b c^{2} x^{3} \sqrt{a + b x + c x^{2}}\, dx + \int 5 b^{2} c x^{2} \sqrt{a + b x + c x^{2}}\, dx + \int 4 a b c x \sqrt{a + b x + c x^{2}}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19731, size = 350, normalized size = 2.12 \begin{align*} \frac{1}{384} \, \sqrt{c x^{2} + b x + a}{\left (2 \,{\left (4 \,{\left (2 \,{\left (8 \,{\left (2 \, c^{3} d^{2} x + 5 \, b c^{2} d^{2}\right )} x + \frac{33 \, b^{2} c^{6} d^{2} + 28 \, a c^{7} d^{2}}{c^{5}}\right )} x + \frac{19 \, b^{3} c^{5} d^{2} + 84 \, a b c^{6} d^{2}}{c^{5}}\right )} x + \frac{b^{4} c^{4} d^{2} + 144 \, a b^{2} c^{5} d^{2} + 48 \, a^{2} c^{6} d^{2}}{c^{5}}\right )} x - \frac{3 \, b^{5} c^{3} d^{2} - 32 \, a b^{3} c^{4} d^{2} - 48 \, a^{2} b c^{5} d^{2}}{c^{5}}\right )} - \frac{{\left (b^{6} d^{2} - 12 \, a b^{4} c d^{2} + 48 \, a^{2} b^{2} c^{2} d^{2} - 64 \, a^{3} c^{3} d^{2}\right )} \log \left ({\left | -2 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )} \sqrt{c} - b \right |}\right )}{256 \, c^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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